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drizzt_fan14

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Whoever gets these answered correct gets a cookie! :)

What I have to do is simplify these:
(this is Algebra II, if that helps)

1.) r to the 1/2 power times s to the 1/3 power (I can't type this right on the keyboard)

2.) b to the negative 1/3 power minus b to the 1/3 power

3.) y square root of 3 minus y equals 7 (solve for y)

4.) 6 minus the square root of 2 times y plus 1 equals 3 (solve for y)

5.) the square root of 2 minus the square root of x plus 6 equals the negative square root of x (solve for x)

6.) (6g-5) to the 1/3 power + 2 = -3 (solve for g)


If you understood all of that, then you're already way ahead of me :lol:
 
I have a friend who would love to help, shall I email him? He's like literally a math genious.
 
OK he's at work right now, when he gets home I'll show him the problems.
 
wow, i hated math...but i took a go at this stuff anyways, but it was hard to tell where you would have parentheses so i put em in where i thought they might be. though i guess that could just make it plain wrong. for the simplifications i wasn't sure how simplified so i did what i could do in my head.


edit: i'll put in the eqations i used...just correct me if ya still need an aswer


1) squared root r times third root s
2) 1/third root b minus third root b
3) 9.562...... (y times squared root 3) minus y = 7
4) -.3458 .... (6 minus sqared root 2)(y plus 1) = 3
5) 2 ....... (squared root 2) minus (squared root (x plus 6)) = -squared root x
6) -20
 
Originally posted by dascoot@Dec 8 2005, 09:02 PM
:wub:
:lol: good thing i was just doing accounting homework, i gots maff on de braynz
 
well, I got the paper back today and all those ones you answered were wrong, lol. Oh well, I couldn't have done any better. This stuff makes no sense. :unsure:
 
Originally posted by drizzt_fan14@Dec 8 2005, 05:11 PM
Whoever gets these answered correct gets a cookie! :)

What I have to do is simplify these:
(this is Algebra II, if that helps)

1.) r to the 1/2 power times s to the 1/3 power (I can't type this right on the keyboard)

2.) b to the negative 1/3 power minus b to the 1/3 power

3.) y square root of 3 minus y equals 7 (solve for y)

4.) 6 minus the square root of 2 times y plus 1 equals 3 (solve for y)

5.) the square root of 2 minus the square root of x plus 6 equals the negative square root of x (solve for x)

6.) (6g-5) to the 1/3 power + 2 = -3 (solve for g)


If you understood all of that, then you're already way ahead of me :lol:
I don't know what any of that means.
 
Sorry Staci :( I saw the answer post so didn't try.. Did they give you the correct solution?
 
Originally posted by Donutos@Dec 9 2005, 02:19 PM
sorry man...aww now i feel like ass
well you're not trust me, everyone in my class got those answers wrong I think. :lol: Math is from Satan.....
 
Mathes My easiest Subject, does that make me a demon...


whats going to happen to Marbles? :eek:
 
Ohh well... If the glove fits.....


Who wants to go kill some random people and make the others lives horrible? :evil:
 
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